This is a rough outline of upcoming tasks: [ ] Prove that CompleteTree.heapUpdateAt returns the element at the given index [ ] Prove that CompleteTree.heapRemoveLastWithIndex and CompleteTree.heapRemoveLast yield the same tree [ ] Prove that CompleteTree.heapRemoveLastWithIndex and CompleteTree.heapRemoveLast yield the same element [ ] Prove that CompleteTree.heapRemoveLastWithIndex indeed removes the last element - This automatically serves as a proof for CompleteTree.heapRemoveLast, once it is shown that they yield the same tree - A potential approach is to show that any index in the resulting tree can be converted into an index in the original tree (by adding one if it's >= the returned index of heapRemoveLastWithIndex), and getting elements from both trees. - **EASIER**: Or just show that except for the n=1 case the value is unchanged. The type signature proves the rest. [ ] Prove that if CompleteTree.indexOf returns some, CompleteTree.get with that result fulfills the predicate. [ ] Prove that CompleteTree.heapUpdateRoot indeed removes the value at the root. [x] A part of this is to show that the new root is not the old root, but rather the passed in value or the root of one of the sub-trees. [ ] The second part is to show that the recursion (if there is one) does not pass on the old root. - Basically that heapUpdateRoot either does not recurse, or recurses with the value it started out with. - This should be relatively straightforward. (left unchanged or left.heapUpdateRoot value and right unchanged or right.heapUpdateRoot value) [x] The last part would be to show that only one element gets removed - Enforced by type signature. [ ] Prove that CompleteTree.heapUpdateAt indeed removes the value at the given index. - Basically making sure that if index != 0 the recursion does either pass on the passed-in value, or the current node's value. - This sounds so trivial, that I am not sure if it's even worth the effort. - The Heap Property that has already been proven shows the rest. [ ] Write the performance part of this file.