import «Common» import Lean.Data.HashMap import Lean.Data.HashSet namespace Day8 inductive Instruction | left | right instance : ToString Instruction where toString a := match a with | Instruction.left => "Left" | Instruction.right => "Right" abbrev WaypointId := String structure Waypoint where id : WaypointId left : WaypointId right : WaypointId deriving Repr -- Okay, the need for different representations in both parts has burnt me once too often. -- This time it's going to be really dumb. private def parseInstructions (input : String) : Except String $ List Instruction := do let mut result := [] for character in input.toList do match character with | 'L' => result := Instruction.left :: result | 'R' => result := Instruction.right :: result | _ => throw s!"Invalid instruction {character}. Only 'L' and 'R' are valid instructions." pure result.reverse private def parseWaypoint (input : String) : Except String Waypoint := if let [id, targets] := input.splitOn " = " |> List.map String.trim then if targets.startsWith "(" && targets.endsWith ")" then let withoutBraces := targets.drop 1 |> flip String.dropRight 1 match withoutBraces.splitOn "," |> List.map String.trim with | [a,b] => pure {id := id, left := a, right := b : Waypoint} | _ => throw s!"Targets need to have 2 entries, separated by ',', but were {targets}" else throw s!"Targets for waypoint need to be enclosed in (), but were {targets}" else throw s!"Waypoint could not be split in ID and targets: {input}" private def parseWaypoints (input : List String) : Except String $ List Waypoint := input.mapM parseWaypoint open Lean in private def validateWaypointLinks (waypoints : List Waypoint) : Bool := let validLinks := HashSet.insertMany HashSet.empty $ waypoints.map Waypoint.id waypoints.all λw ↦ validLinks.contains w.left && validLinks.contains w.right def target : WaypointId := "ZZZ" def start : WaypointId := "AAA" def parse (input : String) : Except String $ List Instruction × List Waypoint := do let lines := input.splitOn "\n" |> List.map String.trim |> List.filter String.notEmpty match lines with | instructions :: waypoints => let instructions ← parseInstructions instructions let waypoints ← parseWaypoints waypoints if let none := waypoints.find? λx ↦ x.id == start then throw s!"Input must contain the waypoint \"{start}\"." if let none := waypoints.find? λx ↦ x.id == target then throw s!"Input must contain the waypoint \"{target}\"" if not $ validateWaypointLinks waypoints then throw "Input contained a waypoint that is not properly linked." return (instructions, waypoints) | [] => throw "Input was empty (or only contained whitespace)." -------------------------------------------------------------------------------------------------------- -- One of my goals for this Advent of Code is to show that the code terminates whenever that's -- possible. In this case, it's not directly possible from the riddle input, but it's possible -- by adding circle detection. So, instead of making the instructions just an infinite list -- I'll treat the case that we run out of instruction in a special way, such that we detect -- if we are lost in the desert. private structure ConnectedWaypoints where left : WaypointId right : WaypointId private def ConnectedWaypoints.get : ConnectedWaypoints → Instruction → WaypointId | {left, right := _}, Instruction.left => left | {left := _, right}, Instruction.right => right -- does a single pass over all instructions. Returns err if no result has been found and another pass is needed. -- error is optional - if none, then there is an inconsistency in the input and we are stuck. private def pass (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (alreadyDoneSteps : Nat) (currentPosition : WaypointId) (instructions : List Instruction) : Except (Option (Nat × WaypointId)) Nat := do if currentPosition == "ZZZ" then return alreadyDoneSteps match instructions with | [] => throw $ some (alreadyDoneSteps, currentPosition) | a :: as => let currentWaypoint := waypoints.find? currentPosition match currentWaypoint with | none => throw none -- should not happen | some currentWaypoint => pass waypoints (alreadyDoneSteps + 1) (currentWaypoint.get a) as private def part1_impl (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (instructions : List Instruction) (possibleStarts : List WaypointId) (alreadyDoneSteps : Nat) (currentPosition : WaypointId) : Option Nat := let remainingStarts := possibleStarts.filter λs ↦ s != currentPosition if remainingStarts.length < possibleStarts.length then -- written this way to make termination_by easy let passResult := pass waypoints alreadyDoneSteps currentPosition instructions match passResult with | Except.ok n => some n | Except.error none => none -- dead end on map. Should not be possible. | Except.error $ some n => part1_impl waypoints instructions remainingStarts n.fst n.snd else none -- walking in circles termination_by possibleStarts.length open Lean in def part1 (input : List Instruction × List Waypoint) : Option Nat := let possibleStarts := input.snd.map Waypoint.id let waypoints : HashMap WaypointId ConnectedWaypoints := HashMap.ofList $ input.snd.map λw ↦ (w.id, {left := w.left, right := w.right : ConnectedWaypoints}) let instructions := input.fst part1_impl waypoints instructions possibleStarts 0 start -------------------------------------------------------------------------------------------------------- -- okay, part 2 is nasty. -- what do we know? -- o) All paths we follow simultaneously have the same path length, as they have common instructions. -- x) This means that once we walk in circles on all of them, we are lost. -- -> That's the way to convince the compiler this program terminates. -- o) We could use the cycle detection to rule out short, cycled paths. -- x) Once a path is in a cycle, the targets repeat at cycle-lenght interval. -- x) I doubt that this would be much faster than brute-force though. -- let's try brute force first. private def parallelPass (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (alreadyDoneSteps : Nat) (currentPositions : List WaypointId) (instructions : List Instruction) : Except (Option (Nat × (List WaypointId))) Nat := do if currentPositions.all λw ↦ w.endsWith "Z" then return alreadyDoneSteps match instructions with | [] => throw $ some (alreadyDoneSteps, currentPositions) | a :: as => let currentWaypoint := currentPositions.mapM waypoints.find? match currentWaypoint with | none => throw none -- should not happen | some currentWaypoints => let nextWaypoints := currentWaypoints.map $ flip ConnectedWaypoints.get a parallelPass waypoints (alreadyDoneSteps + 1) nextWaypoints as private def totalRemainingStarts (s : List (List WaypointId)) : Nat := s.foldl (·+·.length) 0 private def part2_impl (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (instructions : List Instruction) (alreadyDoneSteps : Nat) (possibleStarts : List (List WaypointId)) (currentPositions : List WaypointId) : Option Nat := let remainingStarts := (possibleStarts.zip currentPositions).map λs ↦ s.fst.filter λt ↦ t != s.snd -- I _really_ don't want to prove stuff by hand... Luckily this works. if totalRemainingStarts remainingStarts < totalRemainingStarts possibleStarts then let passResult := parallelPass waypoints alreadyDoneSteps currentPositions instructions match passResult with | Except.ok n => some n | Except.error none => none -- dead end on map. Should not be possible. | Except.error $ some n => part2_impl waypoints instructions n.fst remainingStarts n.snd else none -- walking in circles termination_by totalRemainingStarts possibleStarts -- Okay, tried Brute Force, it did NOT work. Or rather, it might work, but I won't be able to prove -- termination for it. Not that it wouldn't be possible to prove, just I won't manage to. -- The problem is that the termination condition in part2_impl is too soon. -- You can actually see this in the example (for which part2_impl works, but by chance). -- While the goals in each part repeat, they repeat at different rates. -- Soo, we would need to continue even after each part has started walking in circles. -- However, just doing that runs for a very long time without finding a result. -- Sooo, let's be smarter. -- -- Every path consist of 2 segments. The part that leads up to a cycle, and the cycle. -- Both parts can contain goals, but once the cycle starts, the goals repeat with cycle-length. -- A cycle is at least one pass, but can (and does...) consist of multiple passes too. -- We can use part2_impl still - to verify that we do not reach the goals before all our paths start -- cycling. That allows us to only care about cycling paths in the second part of the solution, which -- we only reach if part2_impl does not yield a result (we know it doesn't, but that would be cheating). -- Soo, how can the second part look like? -- For simplicity let's not do this in parallel. Rather, let's find the goals for each start individually -- So, let's just consider a single path (like the one from part1) -- We need to write down the number of steps at which we reach a goal. -- Whenever we remove a remaining start from the possible starts list, we need to note it down, and -- how many steps it took us to get there. -- Once we detect a circle, we can look up -- how many steps we took in total till we startec cycling -- and how many steps it took us to reach the cycle start for the first time -- that's the period of each goal in the cycle. -- For each goal that was found between cycle-start and cycle-end, we can write down an equation: -- x = steps_from_start + cycle_length * n -- n is a Natural number here, not an integer. x is the number of steps at which we pass this goal -- Once we have that information for all goals of all starts, we can combine it: -- That's a set of Diophantine equations. -- -- Or, rather, several sets of Diophantine equations... -- For each combination of goals that are reached in the cycles of the participating paths, we need to -- solve the following system: -- -- We can write each goal for each run in the form x = g0 + n * cg -- Where x is the solution we are looking for, g0 is the number of steps from the start until -- we hit the goal for the first time **in the cycle**, and cg is the cycle length -- -- Once we have those equations, we can combine them pairwise: https://de.wikipedia.org/wiki/Lineare_diophantische_Gleichung -- This allows us to reduce all paths to a single one, which has multiple equations that -- describe when a goal is reached. -- For each of those equations we need to find the first solution that is larger than -- the point where all paths started to cycle. The smallest of those is the result. -- a recurring goal, that starts at "start" and afterwards appears at every "interval". private structure CyclingGoal where start : Nat interval : Nat deriving BEq instance : ToString CyclingGoal where toString g := s!"`g = {g.start} + n * {g.interval}`" private def CyclingGoal.nTh (goal : CyclingGoal) (n : Nat) : Nat := goal.start + n * goal.interval -- Combine two cycling goals into a new cycling goal. This might fail, if they never meet. -- This can for instance happen if they have the same frequency, but different starts. private def CyclingGoal.combine (a b : CyclingGoal) : Option CyclingGoal := -- a.start + n * a.interval = b.start + m * b.interval -- n * a.interval - m * b.interval = b.start - a.start -- we want to do as much as possible in Nat, such that we can easily reason about which numbers are -- positive. Soo let (a, b) := if a.start > b.start then (b,a) else (a,b) let (g, u, _) := Euclid.xgcd a.interval b.interval -- there is no solution if b.start - a.start is not divisible by g let c := (b.start - a.start) let s := c / g if s * g != c then none else let deltaN := b.interval / g let n0 := s * u -- we can use u directly - v would need its sign swapped, but we don't use v. -- a.start + (n0 + t * deltaN)*a.interval -- a.start + n0*a.interval + t * deltaN * a.interval -- we need the first value of t that yields a result >= max(a.start, b.start) -- because that's where our cycles start. let x := ((max a.start b.start : Int) - a.interval * n0 - a.start) let interval := a.interval * deltaN let t0 := x / interval let t0 := if t0 * interval == x || x < 0 then t0 else t0 + 1 -- int division rounds towards zero, so for x < 0 it's already ceil. let start := a.start + n0 * a.interval + t0 * deltaN * a.interval assert! (start ≥ max a.start b.start) let start := start.toNat some {start, interval } private def findCyclingGoalsInPathPass (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (alreadyDoneSteps : Nat) (currentPosition : WaypointId) (instructions : List Instruction) (visitedGoals : List Nat) : Option (Nat × WaypointId × (List Nat)) := do let visitedGoals := if currentPosition.endsWith "Z" then alreadyDoneSteps :: visitedGoals else visitedGoals match instructions with | [] => some (alreadyDoneSteps, currentPosition, visitedGoals) | a :: as => let currentWaypoint := waypoints.find? currentPosition match currentWaypoint with | none => none -- should not happen | some currentWaypoint => findCyclingGoalsInPathPass waypoints (alreadyDoneSteps + 1) (currentWaypoint.get a) as visitedGoals private def findCyclingGoalsInPath_impl (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (instructions : List Instruction) (possibleStarts : List WaypointId) (visitedGoals : List Nat) (visitedStarts : List (WaypointId × Nat)) (currentPosition : WaypointId) (currentSteps : Nat) : List CyclingGoal := let remainingStarts := possibleStarts.filter λs ↦ s != currentPosition if remainingStarts.length < possibleStarts.length then -- written this way to make termination_by easy let visitedStarts := (currentPosition, currentSteps) :: visitedStarts let passResult := findCyclingGoalsInPathPass waypoints currentSteps currentPosition instructions visitedGoals match passResult with | none => [] -- should not happen. Only possible if there's a dead end | some (currentSteps, currentPosition, visitedGoals) => findCyclingGoalsInPath_impl waypoints instructions remainingStarts visitedGoals visitedStarts currentPosition currentSteps else let beenHereWhen := visitedStarts.find? λs ↦ s.fst == currentPosition let beenHereWhen := beenHereWhen.get!.snd --cannot possibly fail let cycleLength := currentSteps - beenHereWhen visitedGoals.filterMap λ n ↦ if n ≥ beenHereWhen then some {start := n, interval := cycleLength : CyclingGoal} else none -- goal was reached before we started to walk in cycles, ignore. termination_by possibleStarts.length private def findCyclingGoalsInPath (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (instructions : List Instruction) (possibleStarts : List WaypointId) (startPosition : WaypointId) : List CyclingGoal := findCyclingGoalsInPath_impl waypoints instructions possibleStarts [] [] startPosition 0 -- returns the number of steps needed until the first _commmon_ goal that cycles is found. private def findFirstCommonCyclingGoal (waypoints : Lean.HashMap WaypointId ConnectedWaypoints) (instructions : List Instruction) (possibleStarts : List WaypointId) (startPositions : List WaypointId) : Option Nat := let cyclingGoals := startPositions.map $ findCyclingGoalsInPath waypoints instructions possibleStarts let combinedGoals : List CyclingGoal := match cyclingGoals with | [] => [] | g :: gs => flip gs.foldl g λc n ↦ c.bind λ cc ↦ n.filterMap λ nn ↦ nn.combine cc let cyclingGoalStarts := combinedGoals.map CyclingGoal.start cyclingGoalStarts.minimum? open Lean in def part2 (input : List Instruction × List Waypoint) : Option Nat := let possibleStarts := input.snd.map Waypoint.id let waypoints : HashMap WaypointId ConnectedWaypoints := HashMap.ofList $ input.snd.map λw ↦ (w.id, {left := w.left, right := w.right : ConnectedWaypoints}) let instructions := input.fst let positions : List WaypointId := (input.snd.filter λ(w : Waypoint) ↦ w.id.endsWith "A").map Waypoint.id part2_impl waypoints instructions 0 (positions.map λ_ ↦ possibleStarts) positions <|> -- if part2_impl fails (it does), we need to dig deeper. findFirstCommonCyclingGoal waypoints instructions possibleStarts positions -------------------------------------------------------------------------------------------------------- open DayPart instance : Parse ⟨8, by simp⟩ (ι := List Instruction × List Waypoint) where parse := parse instance : Part ⟨8,_⟩ Parts.One (ι := List Instruction × List Waypoint) (ρ := Nat) where run := part1 instance : Part ⟨8,_⟩ Parts.Two (ι := List Instruction × List Waypoint) (ρ := Nat) where run := part2 --------------------------------------------------------------------------------------------------------